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J3-1 J3-2 J3-3 J3-4

It s difficult to write about the amount of data that can be stored in an IC memory, simply because the numbers keep increasing so fast. The best way to keep track of the technology is to look at the advertisements for personal computers (PCs). These use RAM ICs in practical, affordable appliances. This book was written with word-processing software on a PC with 640 kilobytes (640 KB) RAM. A kilobyte is about 1,000 bytes; this is about 200 words of text. A double-spaced manuscript page in pica type size (10 characters per inch) has about 200 words. Thus, the RAM in this computer can theoretically hold 640 typewritten pages. That s an average novel. By the time you read this, PCs will probably have several megabytes (MB), perhaps even 1,000 MB, of RAM. A megabyte is about 1,000 KB or a million bytes. How much RAM is really needed by the average PC user Technology eventually comes up against a point of diminishing returns. In consumer word processing, this is already happening. But in other computer endeavors, such as graphics, simulations, interactive games, and high-level mathematics, more RAM simply means more accurate, more realistic, faster, and more powerful results. As technological capabilities increase, demand has a way of following along. (Have you ever noticed this in regards to your spending habits versus your income ) The largest RAMs are found in computers used by commerce and the government.

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is easy to calculate and is equal to the sum of the annual returns (20 percent) divided by the number of returns (2). The compound average return is calculated by (1) dividing the most recent value (A) ($4 at the end of Year 2) by the beginning value (B) ($10 at the beginning of Year 1); (2) taking the resulting ratio to the (1/T) power, where T is the number of years in the compounding period; and (3) subtracting 1.0 to bring it into percentage terms. In math terms, the previous sentence looks like this: [(A/B)^(1/T) 1.0]. The calculation of the compound annual return above is: [($4/$10)^(1/2) 1.0] [(.4)^(1/2) 1.0] [0.6325

IN5 aux. input channel 5 IN6 aux. input channel 6 IN7 aux. input channel 7 IN8 aux. input channel 8

New technologies for IC memory are constantly in the research-and-development (R & D) phase. Thus, you ll hear and read abbreviations and acronyms not mentioned here. So rapidly does the art advance, that manufacturers have trouble keeping their own databooks up to date. It s even worse than the fashion industry. In electronic technology, once something is obsolete, it never comes back. You can t store today s PROMs and hope that they ll be of any use to your grandchildren.

Refer to the text in this chapter if necessary. A good score is at least 18 correct. Answers are in the back of the book. 1. Because of the small size of ICs compared with equivalent circuits made from discrete components: A. More heat is generated.

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536 Integrated circuits and data storage media B. Higher power output is possible. C. Higher switching speeds are attainable. D. Fewer calculations need be done in a given time. 2. Which of the following is not an advantage of ICs over discrete components A. Higher component density. B. Ease of maintenance. C. Greater power capability. D. Lower current consumption. 3. In which of the following devices would you be least likely to find an integrated circuit as the main component A. B. C. D. A radio broadcast transmitter s final amplifier. A notebook computer. A battery-powered calculator. A low-power audio amplifier.

OT1 aux. output channel 1For external siren OT2 aux. output channel 2For external lamp OT3 aux. output channel 3Future use

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